Question

甲車(chē)隊(duì)有汽車(chē)100輛，乙車(chē)隊(duì)有汽車(chē)68輛，要使兩隊(duì)的汽車(chē)一樣多，則需要從甲隊(duì)調(diào)x輛汽車(chē)到乙隊(duì)．由此可列方程為

1. A.
   100-x=68+x
2. B.
   100+x=68-x
3. C.
   x+68=100
4. D.
   100-x=68

Answer 1

A
分析：由題意得到題中存在的等量關(guān)系為：甲隊(duì)原來(lái)的車(chē)輛-調(diào)出的車(chē)輛=乙隊(duì)原來(lái)的車(chē)輛+調(diào)入的車(chē)輛，根據(jù)此等式列方程即可．
解答：設(shè)甲隊(duì)調(diào)x輛汽車(chē)到乙隊(duì)，
由題意得100-x=68+x，
故選A．
點(diǎn)評(píng)：做此類(lèi)題的關(guān)鍵是找出題中存在的等量關(guān)系．