解:(1)根據(jù)題意,是連續(xù)奇數(shù)列,
n=7時(shí),2n-1=7,所以第7項(xiàng)是
,第n項(xiàng)是
;
(2)原式=
(
-
+
-
+…+
-
)
=
×(
-
)
=
×
=
;
(3)原式=
+
+
+…+
=
=
(1-
)
=
.
分析:(1)觀察前邊式子的規(guī)律,可以看到:分母是連續(xù)的兩個(gè)奇數(shù)相乘.對(duì)應(yīng)的第n個(gè)式子的分母是(2n-1)(2n+1);
(2)觀察分母的規(guī)律,發(fā)現(xiàn)分母正好是兩個(gè)連續(xù)的偶數(shù),相差是2.所以拆開(kāi)的時(shí)候,相當(dāng)于擴(kuò)大了2倍,應(yīng)再除以2.然后運(yùn)用抵消的規(guī)律,進(jìn)行計(jì)算;
(3)運(yùn)用整式乘法計(jì)算分母,發(fā)現(xiàn):對(duì)應(yīng)的分母是n
2-(2n+1)+1=n(n-2),運(yùn)用上述方法就可計(jì)算.
點(diǎn)評(píng):熟練運(yùn)用分式的拆分進(jìn)行計(jì)算,尤其注意(3)小題綜合了上述兩種情況的規(guī)律,分別搭配計(jì)算.