Question

若x^p+4x³-qx²-2x+5是關(guān)于x五次四項(xiàng)式，則-p+q=

-5

．

Answer 1

分析：根據(jù)多項(xiàng)式次數(shù)的定義求解．多項(xiàng)式的次數(shù)是多項(xiàng)式中最高次項(xiàng)的次數(shù)，所以可求p，而此多項(xiàng)式又是四項(xiàng)式，故可求q，進(jìn)而可求-p+q．

解答：解：∵x^p+4x³-qx²-2x+5是關(guān)于x的五次四項(xiàng)式，
∴p=5，q=0，
∴-p+q=-5．
故答案是：-5．

點(diǎn)評(píng)：考查了多項(xiàng)式的定義，解題的關(guān)鍵是弄清多項(xiàng)式次數(shù)是多項(xiàng)式中次數(shù)最高的項(xiàng)的次數(shù)．