已知:如圖14,拋物線與軸交于點(diǎn),點(diǎn),與直線相交于點(diǎn),點(diǎn),直線與軸交于點(diǎn).
(1)寫出直線的解析式.
(2)求的面積.
(3)若點(diǎn)在線段上以每秒1個(gè)單位長(zhǎng)度的速度從向運(yùn)動(dòng)(不與重合),同時(shí),點(diǎn)在射線上以每秒2個(gè)單位長(zhǎng)度的速度從向運(yùn)動(dòng).設(shè)運(yùn)動(dòng)時(shí)間為秒,請(qǐng)寫出的面積與的函數(shù)關(guān)系式,并求出點(diǎn)運(yùn)動(dòng)多少時(shí)間時(shí),的面積最大,最大面積是多少?
解:(1)在中,令
,
,··············································· 1分
又點(diǎn)在上
的解析式為·············································································· 2分
(2)由,得 ···················································· 4分
,
,······························································································· 5分
························································································· 6分
(3)過點(diǎn)作于點(diǎn)
······························································································· 7分
·········································································································· 8分
由直線可得:
在中,,,則
,······················································································· 9分
···················································································· 10分
····························································································· 11分
此拋物線開口向下,當(dāng)時(shí),
當(dāng)點(diǎn)運(yùn)動(dòng)2秒時(shí),的面積達(dá)到最大,最大為.···························· 12分
年級(jí) | 高中課程 | 年級(jí) | 初中課程 |
高一 | 高一免費(fèi)課程推薦! | 初一 | 初一免費(fèi)課程推薦! |
高二 | 高二免費(fèi)課程推薦! | 初二 | 初二免費(fèi)課程推薦! |
高三 | 高三免費(fèi)課程推薦! | 初三 | 初三免費(fèi)課程推薦! |
科目:初中數(shù)學(xué) 來源:中考必備’04全國中考試題集錦·數(shù)學(xué) 題型:044
如圖,已知拋物y=x2-ax+a+2與x軸交于A、B兩點(diǎn),與y軸交于點(diǎn)D(0,8),直線DC平行于x軸,交拋物線于另一點(diǎn)C.動(dòng)點(diǎn)P以每秒2個(gè)單位長(zhǎng)度的速度從點(diǎn)C出發(fā),沿C→D運(yùn)動(dòng).同時(shí)、點(diǎn)Q以每秒1個(gè)單位長(zhǎng)度的速度從點(diǎn)A出發(fā),沿A→B運(yùn)動(dòng).連結(jié)PQ、CB.設(shè)點(diǎn)P的運(yùn)動(dòng)時(shí)間為t秒.
(1)求a的值;
(2)當(dāng)t為何值時(shí),PQ平行于y軸;
(3)當(dāng)四邊形PQBC的面積等于14時(shí),求t的值.
查看答案和解析>>
百度致信 - 練習(xí)冊(cè)列表 - 試題列表
湖北省互聯(lián)網(wǎng)違法和不良信息舉報(bào)平臺(tái) | 網(wǎng)上有害信息舉報(bào)專區(qū) | 電信詐騙舉報(bào)專區(qū) | 涉歷史虛無主義有害信息舉報(bào)專區(qū) | 涉企侵權(quán)舉報(bào)專區(qū)
違法和不良信息舉報(bào)電話:027-86699610 舉報(bào)郵箱:58377363@163.com