已知:如圖14,拋物線軸交于點(diǎn),點(diǎn),與直線相交于點(diǎn),點(diǎn),直線軸交于點(diǎn)

(1)寫出直線的解析式.

(2)求的面積.

(3)若點(diǎn)在線段上以每秒1個(gè)單位長(zhǎng)度的速度從運(yùn)動(dòng)(不與重合),同時(shí),點(diǎn)在射線上以每秒2個(gè)單位長(zhǎng)度的速度從運(yùn)動(dòng).設(shè)運(yùn)動(dòng)時(shí)間為秒,請(qǐng)寫出的面積的函數(shù)關(guān)系式,并求出點(diǎn)運(yùn)動(dòng)多少時(shí)間時(shí),的面積最大,最大面積是多少?

解:(1)在中,令

,

,··············································· 1分

點(diǎn)

的解析式為·············································································· 2分

(2)由,得  ···················································· 4分

,······························································································· 5分

························································································· 6分

(3)過點(diǎn)于點(diǎn)

······························································································· 7分

·········································································································· 8分

由直線可得:

中,,,則

,······················································································· 9分

···················································································· 10分

····························································································· 11分

此拋物線開口向下,當(dāng)時(shí),

當(dāng)點(diǎn)運(yùn)動(dòng)2秒時(shí),的面積達(dá)到最大,最大為.···························· 12分

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科目:初中數(shù)學(xué) 來源:中考必備’04全國中考試題集錦·數(shù)學(xué) 題型:044

如圖,已知拋物y=x2-ax+a+2與x軸交于A、B兩點(diǎn),與y軸交于點(diǎn)D(0,8),直線DC平行于x軸,交拋物線于另一點(diǎn)C.動(dòng)點(diǎn)P以每秒2個(gè)單位長(zhǎng)度的速度從點(diǎn)C出發(fā),沿C→D運(yùn)動(dòng).同時(shí)、點(diǎn)Q以每秒1個(gè)單位長(zhǎng)度的速度從點(diǎn)A出發(fā),沿A→B運(yùn)動(dòng).連結(jié)PQ、CB.設(shè)點(diǎn)P的運(yùn)動(dòng)時(shí)間為t秒.

(1)求a的值;

(2)當(dāng)t為何值時(shí),PQ平行于y軸;

(3)當(dāng)四邊形PQBC的面積等于14時(shí),求t的值.

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