Question

如圖，△ABC≌△AEF，AB=AE，∠B=∠E，則下列結(jié)論中不一定成立的是

1. A.
   AC=AF
2. B.
   ∠FAB=∠EAB
3. C.
   EF=BC
4. D.
   ∠EAB=∠FAC

Answer 1

B
分析：全等三角形的對(duì)應(yīng)邊相等，對(duì)應(yīng)角相等，△ABC≌△AEF，可推出AB=AE，∠B=∠E，AC=AF，EF=BC．
解答：∵△ABC≌△AEF
∴AB=AE，∠B=∠E，AC=AF，EF=BC
故A，C選項(xiàng)正確．
∵△ABC≌△AEF
∴∠EAF=∠BAC
∴∠EAB=∠FAC
故D答案也正確．
∠FAB和∠EAB找不到對(duì)應(yīng)關(guān)系，故不一定相等．
故選B．
點(diǎn)評(píng)：本題考查全等三角形的性質(zhì)，全等三角形對(duì)應(yīng)邊相等，對(duì)應(yīng)角相等．