甲、乙兩隊(duì)開展足球?qū)官悾?guī)定每隊(duì)勝一場(chǎng)得3分,平一場(chǎng)得1分,負(fù)一場(chǎng)得0分,甲隊(duì)與乙隊(duì)一共比賽了10場(chǎng),甲隊(duì)保持了不敗記錄,一共得了22分,甲隊(duì)勝了多場(chǎng)?平了多少場(chǎng)?(只列方程)

答案:
解析:

若設(shè)甲隊(duì)勝了x場(chǎng),由于其保持不敗記錄,則其平了(10x)場(chǎng),得3x1·(10x)=22

(1)從比賽情況來(lái)作分析,宜從甲隊(duì)的得分總數(shù)入手尋找等量關(guān)系.

(2)若設(shè)甲隊(duì)勝了x場(chǎng),由于其保持不敗記錄,則其平了(10x)場(chǎng),具體情況列表分析如下:

因而,可列出方程3x1·(10x)=22


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