Question

已知某植物營(yíng)養(yǎng)液的配方含0.3molKCl、0.2molK₂SO₄、0.1molZnSO₄和1LH₂O。若以KCl、K₂SO₄、ZnCl₂和1LH₂O為原料配得相同組成的營(yíng)養(yǎng)液，需 KCl、K₂SO₄、ZnCl₂物質(zhì)的量分別是

A．0.3mol、0.2mol、0.1mol	B．0.1mol、0.2mol、0.3mol
C．0.1mol、0.3mol、0.1mol	D．0.1mol、0.2mol、0.1mol

Answer 1

C

0.1molZnSO₄中有0.1molZn2+，0.1molSO₄^2—；0.3molKCl中有0.3molK⁺，0.3molCl^—；0.2molK₂SO₄中有0.4molK⁺，0.2molSO₄^2—；根據(jù)質(zhì)量守恒定律可得：需 KCl、K₂SO₄、ZnCl₂物質(zhì)的量分別是0.1mol、0.3mol、0.1mol；