已知全集U=A∪B={x∈N|0≤x≤10},A∩(CUB)={1,3,5,7},則集合B=( )
A.{0,2,4,6,8,10}
B.{0,2,4,6,8,9,10}
C.{2,4,6,8,9,10}
D.{2,4,6,8,10}
【答案】分析:由已知中,全集U=A∪B,我們可得(A∩(CUB))∩B=φ,(A∩(CUB))∪B=U,根據(jù)補集的性質(zhì)可得B=CU(A∩(CUB)),進而根據(jù)已知中全集U={x∈N|0≤x≤10},A∩(CUB)={1,3,5,7},得到答案.
解答:解:∵全集U=A∪B={x∈N|0≤x≤10}={0,1,2,3,4,5,6,7,8,9,10},
∴(A∩(CUB))∩B=φ,(A∩(CUB))∪B=U,
故B=CU(A∩(CUB))
又∵A∩(CUB)={1,3,5,7},
∴B={0,2,4,6,8,9,10}
故選B
點評:本題考查的知識點是集合的交、并、補集的混合運算,其中根據(jù)已知中U=A∪B,結(jié)合補集的性質(zhì),判斷出B=CU(A∩(CUB)),將問題轉(zhuǎn)化為求已知集合的補集問題,是解答本題的關(guān)鍵.