Question

由動點(diǎn)Ｐ向圓x² + y²=1引兩條切線PA、PB,切點(diǎn)分別為A、B，∠APB=60°,則動點(diǎn)Ｐ的軌跡方程為 (    )

A  x²+y²=4       B  x²+y²=3          C  x²+y²=2            D  x²+y²=1

Answer 1

A

解析:

據(jù)題意，|PO|＝2,故選A.