(III)設(shè).求證:數(shù)列中任意相鄰的三項(xiàng)都不可能成為等比數(shù)列. 查看更多

 

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設(shè)數(shù)列{an}的前n項(xiàng)和為Sn,且(t-1)Sn=2tan-t-1(其中t為常數(shù),t>0,且t≠1).
(I)求證:數(shù)列{an}為等比數(shù)列;
(II)若數(shù)列{an}的公比q=f(t),數(shù)列{bn}滿足b1=a1,bn+1=數(shù)學(xué)公式f(bn),求數(shù)列{數(shù)學(xué)公式}的通項(xiàng)公式;
(III)設(shè)t=數(shù)學(xué)公式,對(duì)(II)中的數(shù)列{an},在數(shù)列{an}的任意相鄰兩項(xiàng)ak與ak+1之間插入k個(gè)數(shù)學(xué)公式(k∈N*)后,得到一個(gè)新的數(shù)列:a1,數(shù)學(xué)公式,a2,數(shù)學(xué)公式,數(shù)學(xué)公式,a3,數(shù)學(xué)公式,數(shù)學(xué)公式,數(shù)學(xué)公式,a4…,記此數(shù)列為{cn}.求數(shù)列{cn}的前50項(xiàng)之和.

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設(shè)數(shù)列{an}的前n項(xiàng)和為Sn,且(t-1)Sn=2tan-t-1(其中t為常數(shù),t>0,且t≠1).
(I)求證:數(shù)列{an}為等比數(shù)列;
(II)若數(shù)列{an}的公比q=f(t),數(shù)列{bn}滿足b1=a1,bn+1=
1
2
f(bn),求數(shù)列{
1
bn
}的通項(xiàng)公式;
(III)設(shè)t=
1
3
,對(duì)(II)中的數(shù)列{an},在數(shù)列{an}的任意相鄰兩項(xiàng)ak與ak+1之間插入k個(gè)
(-1)k
bk
(k∈N*)后,得到一個(gè)新的數(shù)列:a1
(-1)1
b1
,a2,
(-1)2
b2
(-1)2
b2
,a3,
(-1)3
b3
,
(-1)3
b3
,
(-1)3
b3
,a4…,記此數(shù)列為{cn}.求數(shù)列{cn}的前50項(xiàng)之和.

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設(shè)數(shù)列{an}的前n項(xiàng)和為Sn,且(t-1)Sn=2tan-t-1(其中t為常數(shù),t>0,且t≠1).
(I)求證:數(shù)列{an}為等比數(shù)列;
(II)若數(shù)列{an}的公比q=f(t),數(shù)列{bn}滿足b1=a1,bn+1=f(bn),求數(shù)列{}的通項(xiàng)公式;
(III)設(shè)t=,對(duì)(II)中的數(shù)列{an},在數(shù)列{an}的任意相鄰兩項(xiàng)ak與ak+1之間插入k個(gè)(k∈N*)后,得到一個(gè)新的數(shù)列:a1,,a2,,a3,,,a4…,記此數(shù)列為{cn}.求數(shù)列{cn}的前50項(xiàng)之和.

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設(shè)數(shù)列{an}的前n項(xiàng)和為Sn,且(t-1)Sn=2tan-t-1(其中t為常數(shù),t>0,且t≠1).
(I)求證:數(shù)列{an}為等比數(shù)列;
(II)若數(shù)列{an}的公比q=f(t),數(shù)列{bn}滿足b1=a1,bn+1=f(bn),求數(shù)列{}的通項(xiàng)公式;
(III)設(shè)t=,對(duì)(II)中的數(shù)列{an},在數(shù)列{an}的任意相鄰兩項(xiàng)ak與ak+1之間插入k個(gè)(k∈N*)后,得到一個(gè)新的數(shù)列:a1,,a2,,,a3,,,,a4…,記此數(shù)列為{cn}.求數(shù)列{cn}的前50項(xiàng)之和.

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設(shè)數(shù)列{an}的前n項(xiàng)和為Sn,且(t-1)Sn=2tan-t-1(其中t為常數(shù),t>0,且t≠1).
(I)求證:數(shù)列{an}為等比數(shù)列;
(II)若數(shù)列{an}的公比q=f(t),數(shù)列{bn}滿足b1=a1,bn+1=f(bn),求數(shù)列{}的通項(xiàng)公式;
(III)設(shè)t=,對(duì)(II)中的數(shù)列{an},在數(shù)列{an}的任意相鄰兩項(xiàng)ak與ak+1之間插入k個(gè)(k∈N*)后,得到一個(gè)新的數(shù)列:a1,,a2,,a3,,,a4…,記此數(shù)列為{cn}.求數(shù)列{cn}的前50項(xiàng)之和.

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