考點:有余數(shù)的除法
專題:運算順序及法則
分析:①根據(jù)在有余數(shù)的除法中,余數(shù)總比除數(shù)小,即除數(shù)最小是:余數(shù)+1,進(jìn)而根據(jù)“被除數(shù)=商×除數(shù)+余數(shù)”解答即可;
②根據(jù)在有余數(shù)的除法中,余數(shù)總比除數(shù)小,即余數(shù)最大為:除數(shù)-1,當(dāng)余數(shù)最大時,被除數(shù)最大,進(jìn)而根據(jù)“被除數(shù)=商×除數(shù)+余數(shù)”解答即可
解答:
解:①除數(shù)是:6+1=7
120×7+6
=840+6
=846
②余數(shù)最大是9-1=8
9×9+8
=81+8
=89
故答案為:846,89.
點評:解答此題的關(guān)鍵是:根據(jù)在有余數(shù)的除法中,余數(shù)總比除數(shù)小,得出余數(shù)最大為:除數(shù)-1,最小為1,除數(shù)最小為:余數(shù)+1,然后結(jié)合題意,根據(jù)被除數(shù)、除數(shù)、商和余數(shù)四者之間的關(guān)系進(jìn)行解答