Question

14．計算題

$\frac{5}{9}+\frac{1}{3}$	$\frac{1}{2}-\frac{1}{10}$	$\frac{3}{5}+\frac{1}{15}$	$\frac{8}{9}+\frac{1}{18}$
$\frac{5}{6}-\frac{1}{4}+\frac{1}{3}$	$\frac{1}{5}+\frac{7}{15}+\frac{4}{15}$	$\frac{4}{9}+\frac{1}{10}+\frac{5}{9}$	$\frac{1}{12}+\frac{3}{8}+\frac{11}{12}+\frac{5}{8}$
$\frac{2}{13}$×6	$\frac{9}{14}$×21	$\frac{3}{13}$×$\frac{26}{37}$	$\frac{18}{21}$×$\frac{7}{9}$
$\frac{1}{2}$÷4=	$\frac{4}{5}$÷4=	$\frac{7}{10}$÷$\frac{5}{6}$=	$\frac{5}{7}$÷$\frac{5}{6}$=

Answer 1

分析 根據(jù)分?jǐn)?shù)加減乘除法的計算法則計算即可求解．注意$\frac{4}{9}$+$\frac{1}{10}$+$\frac{5}{8}$變形為$\frac{4}{9}$+$\frac{5}{8}$+$\frac{1}{10}$計算，$\frac{1}{12}$+$\frac{3}{8}$+$\frac{11}{12}$+$\frac{5}{8}$根據(jù)加法交換律和結(jié)合律計算．

解答 解：

$\frac{5}{9}+\frac{1}{3}$=$\frac{8}{9}$	$\frac{1}{2}-\frac{1}{10}$=$\frac{2}{5}$	$\frac{3}{5}+\frac{1}{15}$=$\frac{2}{3}$	$\frac{8}{9}+\frac{1}{18}$=$\frac{17}{18}$
$\frac{5}{6}-\frac{1}{4}+\frac{1}{3}$=$\frac{11}{12}$	$\frac{1}{5}+\frac{7}{15}+\frac{4}{15}$=$\frac{14}{15}$	$\frac{4}{9}+\frac{1}{10}+\frac{5}{9}$=1$\frac{1}{10}$	$\frac{1}{12}+\frac{3}{8}+\frac{11}{12}+\frac{5}{8}$=2
$\frac{2}{13}$×6=$\frac{12}{13}$	$\frac{9}{14}$×21=13$\frac{1}{2}$	$\frac{3}{13}$×$\frac{26}{37}$=$\frac{6}{37}$	$\frac{18}{21}$×$\frac{7}{9}$=$\frac{2}{3}$
$\frac{1}{2}$÷4=$\frac{1}{8}$	$\frac{4}{5}$÷4=$\frac{1}{5}$	$\frac{7}{10}$÷$\frac{5}{6}$=$\frac{21}{25}$	$\frac{5}{7}$÷$\frac{5}{6}$=$\frac{6}{7}$

點評 考查了分?jǐn)?shù)加減乘除法，關(guān)鍵是熟練掌握計算法則正確進(jìn)行計算．