Question

用“偶數(shù)”和“奇數(shù)”填空：
偶數(shù)+

 

=偶數(shù)；            
偶數(shù)×偶數(shù)=

 

；

 

+奇數(shù)=奇數(shù)；            
奇數(shù)×奇數(shù)=

 

；
奇數(shù)+

 

=偶數(shù)；            
奇數(shù)×

 

=偶數(shù)．

Answer 1

考點(diǎn)：奇數(shù)與偶數(shù)的初步認(rèn)識(shí)

專題：數(shù)的整除

分析：根據(jù)偶數(shù)、奇數(shù)的性質(zhì)：偶數(shù)±偶數(shù)=偶數(shù)，奇數(shù)±奇數(shù)=偶數(shù)，奇數(shù)±偶數(shù)=奇數(shù)，偶數(shù)×偶數(shù)=偶數(shù)，奇數(shù)×奇數(shù)=奇數(shù)，奇數(shù)×偶數(shù)=偶數(shù)，據(jù)此解答．

解答： 解：偶數(shù)+偶數(shù)=偶數(shù)；            
偶數(shù)×偶數(shù)=偶數(shù)；
偶數(shù)+奇數(shù)=奇數(shù)；            
奇數(shù)×奇數(shù)=奇數(shù)；
奇數(shù)+奇數(shù)=偶數(shù)；            
奇數(shù)×偶數(shù)=偶數(shù)．
故答案為：偶數(shù)，偶數(shù)，偶數(shù)，奇數(shù)，奇數(shù)，偶數(shù)，

點(diǎn)評(píng)：此題考查的目的是理解掌握偶數(shù)與奇數(shù)的性質(zhì)及應(yīng)用．