Question

6．用遞等式計算．
$\frac{6}{7}$×$\frac{35}{12}$×$\frac{6}{5}$
$\frac{11}{35}$×15÷$\frac{22}{7}$
$\frac{13}{16}$÷$\frac{3}{4}$÷$\frac{26}{3}$．

Answer 1

分析 ①先約分再計算．
②把除法變成乘法，先約分再計算．
③把除法變成乘法，先約分再計算．

解答 解：①$\frac{6}{7}$×$\frac{35}{12}$×$\frac{6}{5}$
=$\frac{5}{2}×\frac{6}{5}$
=3

②$\frac{11}{35}$×15÷$\frac{22}{7}$
=$\frac{11}{35}×\frac{7}{22}×15$
=$\frac{1}{10}×15$
=$\frac{3}{2}$

③$\frac{13}{16}$÷$\frac{3}{4}$÷$\frac{26}{3}$
=$\frac{13}{16}×\frac{4}{3}×\frac{3}{26}$
=$\frac{1}{8}$

點評 本題主要考查分數四則混合運算的計算順序．