遞等式計算(能簡便的要用簡便方法計算).
①(1÷0.5+0.5÷1)×3.2
②0.25×3.7×(3.8+0.2)
③52.8÷[18.2-(4.24÷0.8-0.3)]
④0.375×8-0.8+7.25×0.8.
解:(1)(1÷0.5+0.5÷1)×3.2,
=(2+0.5)×3.2,
=2.5×4×0.8,
=10×0.8,
=8;
(2)0.25×3.7×(3.8+0.2),
=0.25×4×3.7,
=1×3.7,
=3.7;
(3)52.8÷[18.2-(4.24÷0.8-0.3)],
=52.8÷[18.2-(5.3-0.3)],
=52.8÷[18.2-5],
=52.8÷13.2,
=4;
(4)0.375×8-0.8+7.25×0.8,
=0.8×(3.75-1+7.25),
=0.8×10,
=8.
分析:(1)算出括號里面的得數(shù)后,化3.2=4×0.8解答,
(2)先算出(3.8+0.2)=4,再運用乘法交換律解答,
(3)依據(jù)四則運算計算方法解答,
(4)化0.375×8=3.75×0.8,運用乘法分配律解答.
點評:本題主要考查學(xué)生對于四則運算計算方法,以及四則運算簡便算法的掌握.