35×(4×2)×25;            
990÷[2×(17+28)]
(270+35×6)÷80;            
88×13-13×68.

解:(1)35×(4×2)×25
=35×4×2×25,
=(35×2)×(4×25),
=70×100,
=7000;

(2)990÷[2×(17+28)]
=990÷[2×45],
=990÷90,
=11;

(3)(270+35×6)÷80
=(270+210)÷80,
=480÷80,
=6;

(4)88×13-13×68
=(88-68)×13,
=20×13,
=260.
分析:算式(1)可根據(jù)乘法結合律及交換律進行計算;
算式(2)(3)根據(jù)四則混合運算順序計算即可:先算乘除,再算加減,有括號的要先算括號里面的.
算式(4)可根據(jù)乘法分配律進行計算.
點評:當算式中同時含有小括號與中括號時,要先算小括號里面的,再算中括號里面的.
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