Question

兩個連續(xù)正整數(shù)的和（　�。�

A．一定是奇數(shù)

B．一定是偶數(shù)

C．一定能被2整除

D．一定能被5整除

Answer 1

分析：根據(jù)奇數(shù)與偶數(shù)的性質(zhì)，奇數(shù)與奇數(shù)的和是偶數(shù)，積數(shù)與偶數(shù)的和是奇數(shù)，偶數(shù)與偶數(shù)的和是偶數(shù)．據(jù)此解答．

解答：解：最小的正整數(shù)是1，兩個連續(xù)正整數(shù)中，一個奇數(shù)一個偶數(shù)，所以兩個連續(xù)正整數(shù)的和是奇數(shù)．
故選：A．

點評：此題考查的目的是理解掌握奇數(shù)與偶數(shù)的性質(zhì)．奇數(shù)與奇數(shù)的和是偶數(shù)，積數(shù)與偶數(shù)的和是奇數(shù)，偶數(shù)與偶數(shù)的和是偶數(shù)．