Question

【題目】根據(jù)題意， 補全解題過程：

如圖，∠AOB=90°，OE平分∠AOC，OF平分∠BOC． 求∠EOF的度數(shù).

解：因為OE平分∠AOC，OF平分∠BOC

所以∠EOC =∠AOC，∠FOC =________.

所以∠EOF =∠EOC-________

=(∠AOC-_______)

= ________

=_________°.

Answer 1

【答案】∠BOC ∠FOC ∠BOC ∠AOB 45°

【解析】

根據(jù)角平分線的定義可得∠EOC =∠AOC，∠FOC =∠BOC，然后根據(jù)∠EOF =∠EOC-∠FOC進行計算解答即可.

解：因為OE平分∠AOC，OF平分∠BOC

所以∠EOC =∠AOC，∠FOC =_∠BOC _______.

所以∠EOF =∠EOC-_∠FOC _______

=(∠AOC-_∠BOC ______)

= ∠AOB

=_____45____°.