Question

（8分）某手機(jī)專(zhuān)營(yíng)店代理銷(xiāo)售A、B兩種型號(hào)手機(jī)．手機(jī)的進(jìn)價(jià)、售價(jià)如下表：

型  號(hào)	A	B
進(jìn)  價(jià)	1200元/部	1000元/部
售  價(jià)	1380元/部	1200元/部

 

 

 

 

（1）第一季度：用36000元購(gòu)進(jìn) A、B兩種型號(hào)的手機(jī)，全部售完后獲利6300元，求第一季度購(gòu)進(jìn)A、B兩種型號(hào)手機(jī)的數(shù)量；

1.（2）第二季度：計(jì)劃購(gòu)進(jìn)A、B兩種型號(hào)手機(jī)共34部，且不超出第一季度的購(gòu)機(jī)總費(fèi)用，則A型號(hào)手機(jī)最多能購(gòu)多少部？

 

Answer 1

 

1.（1）解：設(shè)該專(zhuān)營(yíng)店第一季度購(gòu)進(jìn)A、B兩種型號(hào)手機(jī)的數(shù)量分別為x部和y部．····· 1分

由題意可知： ·········································································· 3分

       解得：

答：該專(zhuān)營(yíng)店本次購(gòu)進(jìn)A、B兩種型號(hào)手機(jī)的數(shù)分別為15部和18部．··························· 4分

 

2.（2）解：設(shè)第二季度購(gòu)進(jìn)A型號(hào)手機(jī)a部．······························································· 5分

由題意可知：1200a+1000(34－a)≤36000，··································································· 6分

解得：a≤10·················································································································· 7分

不等式的最大整數(shù)解為10

答：第二季度最多能購(gòu)A型號(hào)手機(jī)10部．····································································· 8分

 

解析:略