如圖所示,質(zhì)量m=1Kg的小球穿在長(zhǎng)L=0.8m的斜桿上,斜桿與水平方向成α=37°角,斜桿固定不動(dòng),小球與斜桿間的動(dòng)摩擦因數(shù)μ=0.75.小球受水平向左的拉力F=2N,從斜桿的頂端由靜止開始下滑,求(sin37°=0.6,cos37°=0.8,g=10m/s2)                                                                                                                            

(1)小球運(yùn)動(dòng)的加速度大;                                                                                

(2)小球運(yùn)動(dòng)到斜桿底端時(shí)的速度大小.                                                              

                                                                                              

                                                                                                                               


(1)沿桿子方向:Fcosα+mgsinα﹣μN(yùn)=ma

垂直桿子方向:Fsinα+N=mgcosα

代入數(shù)據(jù)解得a=2.5  m/s2

(2)根據(jù)v2=2aL得,

v==2 m/s.

答:(1)小球運(yùn)動(dòng)的加速度大小為2.5m/s2

(2)小球運(yùn)動(dòng)到斜桿底端時(shí)的速度大小為2m/s.


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