(1)桃樹(shù)比蘋(píng)果樹(shù)多25%,蘋(píng)果樹(shù)有多少棵?列式:
桃樹(shù)的棵數(shù)÷(1+25%)
桃樹(shù)的棵數(shù)÷(1+25%)

(2)蘋(píng)果樹(shù)比桃樹(shù)多25%,蘋(píng)果樹(shù)有多少棵?列式:
桃樹(shù)的棵數(shù)×(1+25%)
桃樹(shù)的棵數(shù)×(1+25%)

(3)桃樹(shù)比蘋(píng)果樹(shù)少25%,蘋(píng)果樹(shù)有多少棵?列式:
桃樹(shù)的棵數(shù)÷(1-25%)
桃樹(shù)的棵數(shù)÷(1-25%)

(4)桃樹(shù)比蘋(píng)果樹(shù)少25%,蘋(píng)果樹(shù)有多少棵?列式:
桃樹(shù)的棵數(shù)×(1-25%)
桃樹(shù)的棵數(shù)×(1-25%)
分析:(1)把蘋(píng)果樹(shù)的棵數(shù)看成單位“1”,它的(1+25%)對(duì)應(yīng)的數(shù)量是桃樹(shù)的棵數(shù),由此用除法求出蘋(píng)果樹(shù)的棵數(shù);
(2)把桃樹(shù)的棵數(shù)看成單位“”1,用桃樹(shù)的棵數(shù)乘上(1+25%)就是蘋(píng)果樹(shù)的棵數(shù);
(3)把蘋(píng)果樹(shù)的棵數(shù)看成單位“1”,它的(1-25%)對(duì)應(yīng)的數(shù)量是桃樹(shù)的棵數(shù),由此用除法求出蘋(píng)果樹(shù)的棵數(shù);
(4)把桃樹(shù)的棵數(shù)看成單位“”1,用桃樹(shù)的棵數(shù)乘上(1-25%)就是蘋(píng)果樹(shù)的棵數(shù).
解答:解:(1)桃樹(shù)的棵數(shù)÷(1+25%);

(2)桃樹(shù)的棵數(shù)×(1+25%);

(3)桃樹(shù)的棵數(shù)÷(1-25%);

(4)桃樹(shù)的棵數(shù)×(1-25%).
故答案為:桃樹(shù)的棵數(shù)÷(1+25%);桃樹(shù)的棵數(shù)×(1+25%);桃樹(shù)的棵數(shù)÷(1-25%);桃樹(shù)的棵數(shù)×(1-25%).
點(diǎn)評(píng):解答此類(lèi)問(wèn)題,首先找清單位“1”,進(jìn)一步理清解答思路,列式的順序,從而較好的解答問(wèn)題.
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