如圖,已知點(diǎn)A(0,1),B(0,﹣1),以點(diǎn)A為圓心,AB為半徑作圓,交x軸的正半軸于點(diǎn)C,則∠BAC等于      度.                                                                       

                                                                       


 60                                                                                               

【考點(diǎn)】垂徑定理;坐標(biāo)與圖形性質(zhì);等邊三角形的判定與性質(zhì);勾股定理.                    

【分析】求出OA、AC,通過余弦函數(shù)即可得出答案.                                   

【解答】解:∵A(0,1),B(0,﹣1),                                            

∴AB=2,OA=1,                                                                               

∴AC=2,                                                                                          

在Rt△AOC中,cos∠BAC==,                                                        

∴∠BAC=60°,                                                                                  

故答案為60.                                                                                    

【點(diǎn)評】本題考查了垂徑定理的應(yīng)用,關(guān)鍵是求出AC、OA的長.                

                                                                                                       


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