解答題:(1) (-2mx2)•(-3m2x)3(2)(4a3-6a2+9a)÷(-2a)
(3)6a3-(a2+1)•a (4)(x-2y)(x+2y)-(x+2y)2
解:(1) (-2mx
2)•(-3m
2x)
3,
=(-2mx
2)•(-27m
6x
3),
=54m
7x
5;
(2)(4a
3-6a
2+9a)÷(-2a)=-2a
2+3a-
;
(3)6a
3-(a
2+1)•a,
=6a
3-a
3-a,
=5a
3-a;
(4)(x-2y)(x+2y)-(x+2y)
2,
=x
2-4y
2-(x
2+4xy+4y
2),
=x
2-4y
2-x
2-4xy-4y
2,
=-8y
2-4xy.
分析:(1)根據(jù)積的乘方與單項(xiàng)式的乘法法則計(jì)算;
(2)運(yùn)用多項(xiàng)式除以單項(xiàng)式的法則計(jì)算;
(3)先算乘法,再合并同類項(xiàng);
(4)先運(yùn)用平方差公式與完全平方公式計(jì)算,再合并同類項(xiàng).
點(diǎn)評(píng):本題考查了積的乘方,單項(xiàng)式的乘法,多項(xiàng)式除單項(xiàng)式,平方差公式,完全平方公式,熟練掌握各種運(yùn)算法則和性質(zhì)是解題的關(guān)鍵,計(jì)算時(shí)要注意運(yùn)算符號(hào)的處理.