Question

計(jì)算：

(1+ax)2-(a+x)2

(1+bx)2-(b+x)2

÷

(1+ay)2-(a+y)2

(1+by)2-(b+y)2

．

Answer 1

考點(diǎn)：分式的混合運(yùn)算

專題：計(jì)算題

分析：原式利用除法法則變形，約分即可得到結(jié)果．

解答：解：原式=

(1+ax+a+x)(1+ax-a-x)

(1+bx+b+x)(1+bx-b-x)

•

(1+by+b+y)(1+by-b-y)

(1+ay+a+y)(1+ay-a-y)

=

(a+1)(x+1)(a-1)(x-1)

(b+1)(x+1)(x-1)(b-1)

•

(b+1)(y+1)(b-1)(y-1)

(a+1)(y+1)(a-1)(y-1)

=1．

點(diǎn)評(píng)：此題考查了分式的混合運(yùn)算，熟練掌握運(yùn)算法則是解本題的關(guān)鍵．